3.4.4 \(\int \frac {(e+f x)^2}{(a+b \sin (c+\frac {d}{x}))^2} \, dx\) [304]

Optimal. Leaf size=25 \[ \text {Int}\left (\frac {(e+f x)^2}{\left (a+b \sin \left (c+\frac {d}{x}\right )\right )^2},x\right ) \]

[Out]

Unintegrable((f*x+e)^2/(a+b*sin(c+d/x))^2,x)

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Rubi [A]
time = 0.02, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {(e+f x)^2}{\left (a+b \sin \left (c+\frac {d}{x}\right )\right )^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[(e + f*x)^2/(a + b*Sin[c + d/x])^2,x]

[Out]

Defer[Int][(e + f*x)^2/(a + b*Sin[c + d/x])^2, x]

Rubi steps

\begin {align*} \int \frac {(e+f x)^2}{\left (a+b \sin \left (c+\frac {d}{x}\right )\right )^2} \, dx &=\int \frac {(e+f x)^2}{\left (a+b \sin \left (c+\frac {d}{x}\right )\right )^2} \, dx\\ \end {align*}

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Mathematica [A]
time = 74.51, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(e+f x)^2}{\left (a+b \sin \left (c+\frac {d}{x}\right )\right )^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[(e + f*x)^2/(a + b*Sin[c + d/x])^2,x]

[Out]

Integrate[(e + f*x)^2/(a + b*Sin[c + d/x])^2, x]

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Maple [A]
time = 0.60, size = 0, normalized size = 0.00 \[\int \frac {\left (f x +e \right )^{2}}{\left (a +b \sin \left (c +\frac {d}{x}\right )\right )^{2}}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((f*x+e)^2/(a+b*sin(c+d/x))^2,x)

[Out]

int((f*x+e)^2/(a+b*sin(c+d/x))^2,x)

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Maxima [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)^2/(a+b*sin(c+d/x))^2,x, algorithm="maxima")

[Out]

-(2*(a*b*f^2*x^4 + 2*a*b*f*x^3*e + a*b*x^2*e^2)*cos(2*(c*x + d)/x)*cos((c*x + d)/x) + 2*(a*b*f^2*x^4 + 2*a*b*f
*x^3*e + a*b*x^2*e^2)*cos((c*x + d)/x) + ((a^2*b^2 - b^4)*d*cos(2*(c*x + d)/x)^2 + 4*(a^4 - a^2*b^2)*d*cos((c*
x + d)/x)^2 + 4*(a^3*b - a*b^3)*d*cos((c*x + d)/x)*sin(2*(c*x + d)/x) + (a^2*b^2 - b^4)*d*sin(2*(c*x + d)/x)^2
+ 4*(a^4 - a^2*b^2)*d*sin((c*x + d)/x)^2 + 4*(a^3*b - a*b^3)*d*sin((c*x + d)/x) + (a^2*b^2 - b^4)*d - 2*(2*(a
^3*b - a*b^3)*d*sin((c*x + d)/x) + (a^2*b^2 - b^4)*d)*cos(2*(c*x + d)/x))*integrate(-2*(2*(a^2*d*f^2*x^2 + 2*a
^2*d*f*x*e + a^2*d*e^2)*cos((c*x + d)/x)^2 + 2*(a^2*d*f^2*x^2 + 2*a^2*d*f*x*e + a^2*d*e^2)*sin((c*x + d)/x)^2
+ (2*(2*a*b*f^2*x^3 + 3*a*b*f*x^2*e + a*b*x*e^2)*cos((c*x + d)/x) - (a*b*d*f^2*x^2 + 2*a*b*d*f*x*e + a*b*d*e^2
)*sin((c*x + d)/x))*cos(2*(c*x + d)/x) + 2*(2*a*b*f^2*x^3 + 3*a*b*f*x^2*e + a*b*x*e^2)*cos((c*x + d)/x) + (4*b
^2*f^2*x^3 + 6*b^2*f*x^2*e + 2*b^2*x*e^2 + (a*b*d*f^2*x^2 + 2*a*b*d*f*x*e + a*b*d*e^2)*cos((c*x + d)/x) + 2*(2
*a*b*f^2*x^3 + 3*a*b*f*x^2*e + a*b*x*e^2)*sin((c*x + d)/x))*sin(2*(c*x + d)/x) + (a*b*d*f^2*x^2 + 2*a*b*d*f*x*
e + a*b*d*e^2)*sin((c*x + d)/x))/((a^2*b^2 - b^4)*d*cos(2*(c*x + d)/x)^2 + 4*(a^4 - a^2*b^2)*d*cos((c*x + d)/x
)^2 + 4*(a^3*b - a*b^3)*d*cos((c*x + d)/x)*sin(2*(c*x + d)/x) + (a^2*b^2 - b^4)*d*sin(2*(c*x + d)/x)^2 + 4*(a^
4 - a^2*b^2)*d*sin((c*x + d)/x)^2 + 4*(a^3*b - a*b^3)*d*sin((c*x + d)/x) + (a^2*b^2 - b^4)*d - 2*(2*(a^3*b - a
*b^3)*d*sin((c*x + d)/x) + (a^2*b^2 - b^4)*d)*cos(2*(c*x + d)/x)), x) + 2*(b^2*f^2*x^4 + 2*b^2*f*x^3*e + b^2*x
^2*e^2 + (a*b*f^2*x^4 + 2*a*b*f*x^3*e + a*b*x^2*e^2)*sin((c*x + d)/x))*sin(2*(c*x + d)/x))/((a^2*b^2 - b^4)*d*
cos(2*(c*x + d)/x)^2 + 4*(a^4 - a^2*b^2)*d*cos((c*x + d)/x)^2 + 4*(a^3*b - a*b^3)*d*cos((c*x + d)/x)*sin(2*(c*
x + d)/x) + (a^2*b^2 - b^4)*d*sin(2*(c*x + d)/x)^2 + 4*(a^4 - a^2*b^2)*d*sin((c*x + d)/x)^2 + 4*(a^3*b - a*b^3
)*d*sin((c*x + d)/x) + (a^2*b^2 - b^4)*d - 2*(2*(a^3*b - a*b^3)*d*sin((c*x + d)/x) + (a^2*b^2 - b^4)*d)*cos(2*
(c*x + d)/x))

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Fricas [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)^2/(a+b*sin(c+d/x))^2,x, algorithm="fricas")

[Out]

integral(-(f^2*x^2 + 2*f*x*e + e^2)/(b^2*cos((c*x + d)/x)^2 - 2*a*b*sin((c*x + d)/x) - a^2 - b^2), x)

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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)**2/(a+b*sin(c+d/x))**2,x)

[Out]

Timed out

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Giac [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((f*x+e)^2/(a+b*sin(c+d/x))^2,x, algorithm="giac")

[Out]

integrate((f*x + e)^2/(b*sin(c + d/x) + a)^2, x)

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Mupad [A]
time = 0.00, size = -1, normalized size = -0.04 \begin {gather*} \int \frac {{\left (e+f\,x\right )}^2}{{\left (a+b\,\sin \left (c+\frac {d}{x}\right )\right )}^2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e + f*x)^2/(a + b*sin(c + d/x))^2,x)

[Out]

int((e + f*x)^2/(a + b*sin(c + d/x))^2, x)

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